z^2+3z+1-2i=0

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Solution for z^2+3z+1-2i=0 equation:


Simplifying
z2 + 3z + 1 + -2i = 0

Reorder the terms:
1 + -2i + 3z + z2 = 0

Solving
1 + -2i + 3z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -2i + 3z + -1 + z2 = 0 + -1

Reorder the terms:
1 + -1 + -2i + 3z + z2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2i + 3z + z2 = 0 + -1
-2i + 3z + z2 = 0 + -1

Combine like terms: 0 + -1 = -1
-2i + 3z + z2 = -1

Add '-3z' to each side of the equation.
-2i + 3z + -3z + z2 = -1 + -3z

Combine like terms: 3z + -3z = 0
-2i + 0 + z2 = -1 + -3z
-2i + z2 = -1 + -3z

Add '-1z2' to each side of the equation.
-2i + z2 + -1z2 = -1 + -3z + -1z2

Combine like terms: z2 + -1z2 = 0
-2i + 0 = -1 + -3z + -1z2
-2i = -1 + -3z + -1z2

Divide each side by '-2'.
i = 0.5 + 1.5z + 0.5z2

Simplifying
i = 0.5 + 1.5z + 0.5z2

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